2x^2+31x-6.5=0

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Solution for 2x^2+31x-6.5=0 equation: 



2x^2+31x-6.5=0

a = 2; b = 31; c = -6.5;
Δ = b2-4ac
Δ = 312-4·2·(-6.5)
Δ = 1013
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-\sqrt{1013}}{2*2}=\frac{-31-\sqrt{1013}}{4}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+\sqrt{1013}}{2*2}=\frac{-31+\sqrt{1013}}{4}
$

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